The Rubidium (Rb) and the Strontium (Sr) are two chemical elements generally existing with the state of traces in the rocks. They replace partly for the Potassium for rubidium and the Calcium for strontium. Thus the minerals rich in potassium are generally rich in rubidium and those rich in calcium often present high percentages of strontium. It happens that strontium is a major element of certain minerals, it is the case in particular strontium carbonate of SrCO3 formula (strontianite) or celestite SrSO4 (célestite).

These two elements exist in nature in the form of several Isotope S, two for rubidium, 85Rb and 87Rb and four for strontium, 84Sr, 86Sr, 87Sr and 88Sr. Only one of them, the 87Rb, is radioactive . It disintegrates in 87Sr which, is to him a stable isotope of strontium like are, moreover, the three others. This Disintegration, for one, leads to the emission of an electron; it is thus a Radioactivité known as " beta less " that one can schematize by:

{} ^ {\ rm {has}} _ {\ rm {Z}} \ rm {M} \ longrightarrow {} ^ {\ rm {has}} _ {\ rm {Z+1}} \ rm {Me} + e^ {-} + \ naked bar {\} _ {E} + \ mathbf {Q}

{} _ {37} ^ {87} \ rm {Rb} \ longrightarrow {} _ {38} ^ {87} \ rm {Sr} + e^- + \ naked bar {\} _ {E} + \ mathbf {Q}

Let us note as of now that 87Rb and 87Sr are two isobar S, i.e. two atomic species having the same mass number but differing by their numbers of protons. That poses a problem in mass spectrometry because the mass spectrometers used for the measurement of the isotopic reports/ratios of Sr generally have a weak resolution (300-400), which does not make it possible to separate 87Rb from 87Sr. It is thus essential to separate the two elements before measurement with the mass spectrometer. As in the case of the method of dating by the couple samarium-neodymium (Sm-Nd) it is generally necessary to dissolve the samples in order to carry out the separation of rudidium and strontium by ionic chromatography. This stage is carried out in clean room in order to limit the contamination of the sample.

The recent appearance of the mass spectrometers to plasma source coupled to a laser (LA-MC-ICPMS, Laser Ablation Multicollector Inductively Coupled Plasma Spectrometer Farmhouse) now makes it possible to carry out certain in-situ measurements on a polished section of rock, thus avoiding the complex phase of chemical dissolution-separation, but this method is still experimental for the couple Rb-Sr.

A certain number of conditions must be joined together so that the method Rb-Sr is applicable, in particular:

  • the whole of the rocks or analyzed minerals must have crystallized starting from a common source of strontium, i.e. the initial reports/ratios 87Sr/86Sr are equal.
  • the system must be remained closed since its formation, i.e. it did not lose or did not gain of rubidium or strontium. These exchanges are possible for example if the rock is crossed by fluids, when it is subjected to a metamorphic episode, or by deterioration on the surface.

At the end of the crystallization of a magmatic rock, each mineral constituting it integrated initial quantities different from the four isotopes of the strontium and both of rubidium.

Strontium 87 present today in a rock is thus the sum of strontium 87 present at the origin, with the formation of the rock and strontium 87 product by the disintegration of rubidium 87. We can write in a synthetic way:

{} ^ {87} \ rm {current Sr} {} _ {} = {} ^ {87} \ rm {initial Sr} {} _ {} + {} ^ {87} \ rm {Sr}

When a radioactive isotope disintegrates, the variation of this isotope follows a function of the time NR (T) which obeys the law N' (T) = - \ lambda NR (T) \, . This differential equation has as a solution the functions of the type N (T) = N_0 exp^ {- \ lambda T} \, .

\ lambda \, is called " constant of disintegration ". It is related to another constant characteristic of this disintegration, T , called " period of half-life " , time with the end of which there remains nothing any more but half of the isotope present at the beginning.

We thus have: \ frac {N_0} {2} = N_0 exp^ {- \ lambda T} from where \ lambda = \ frac {ln (2)}{T} .

For the couple (87Rb/87Sr), T are worth approximately 49 billion years and thus λ = 1,42 10-11/an .

The equation above becomes:

{}^{87}\!Current Sr_ {} = {} ^ {87} \! Initial Sr_ {} + {} ^ {87} \! Current Rb_ {} (exp^ {\ lambda T} - 1)

Indeed, the desinteration partial of 87Rbinitial results in the difference: 87Rbinitial - 87Rbactuel and like 87Rbactuel = 87Rbinitiale-λt, we have well:

{}^{87}\!Initial Rb_ {} - {} ^ {87} \! Current Rb_ {} = {} ^ {87} \! Current Rb_ {} (exp^ {\ lambda T} - 1)

The problem is that we are opposite two unknown factors: 87Srinitial and T; however, we have only one equation…

This problem will be skilfully solved by knowing that the isotopic report/ratio 87Srinitial/86Srinitial remained identical since the origin and that the quantity of isotope 86Sr (stable isotope) does not vary during time.

By dividing the equation above by 86Sractuel which is equal to 86Srinitial besides, we obtain:

{}^{87}\!Current Sr_ {}/{} ^ {86} \! Current Sr_ {} = {} ^ {87} \! Initial Sr_ {}/{} ^ {86} \! Current Sr_ {} + ({} ^ {87} \! Current Rb_ {}/{} ^ {86} \! Current Sr_ {}) (exp^ {\ lambda T} - 1)

Two rocks resulting from the same magma will present the same initial report/ratio 87Srinitial/86Sractuel but of the 87Sractuel ratios/86Sractuel and 87Rbactuel/86Sractuel different.

We will have two unknown factors then but also here, in this case, two equations… It is necessary then:
  • to measure the concentrations of rubidium and strontium in the total rock and/or separate minerals (muscovite, biotite…) what can be carried out various manners. The method generally considered most reliable is the measurement of the concentrations of rubidium and strontium by isotopic dilution. In the case of strontium if the tracer used for the isotopic measurement of dilution is enriched in 84Sr and gauged well, only one measurement with the mass spectrometer makes it possible to obtain the measurement of the 87Sr/86Sr report/ratio and the Sr content of the sample.
  • to measure the isotopic composition of strontium in la/les rock total and the mineral fractions
  • to then place on the x-axis the values of the 87Rbactuel ratios/86Sractuel and to place on the y-axis the values of the corresponding 87Sractuel ratios/86Sractuel,

  • to release the line of tendency which emerges from the group of dots,
  • to calculate the slope " of it; p"
  • and finally to deduce the age from it from the rocks by the equation t = {ln (p+1)}/\ lambda.

detailed Article: isotopic Geology

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